Зад.1 от Физика II - Е

Дад:Т=0,02;F=300;fi=-pi/4;A=4cm.

a)Zakon za trepteneto;b)koeficent na elasti4nost "k";c)masa na tqloto;d)palna meh energiq "E".

a)

parvo -> ω=2pi.f   a   f=1/T

x=A.cos(ωt+φ)=4.cos(ωt-pi/4)=4.cos((2pi.t/T)-pi/4)=...=4.cos(pi(400t-1)/4)

b)F=k.A => k=F/A

c)

Parvo ω^2=k/m

T=2pi/ω=2pi/(koren(k/m))=... => m=T^2.k/4(pi)^2

d)

E=k.A^2/2

Dad. d=0,8cm;λ=1,06;L=15.10^3m;

D=ω

D=2θ.L     (1)

2θ=2,44.λ/d

i na (1) namirash D.